4[(6x+1)-8]=3(2x-7)

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Solution for 4[(6x+1)-8]=3(2x-7) equation:


Simplifying
4[(6x + 1) + -8] = 3(2x + -7)

Reorder the terms:
4[(1 + 6x) + -8] = 3(2x + -7)

Remove parenthesis around (1 + 6x)
4[1 + 6x + -8] = 3(2x + -7)

Reorder the terms:
4[1 + -8 + 6x] = 3(2x + -7)

Combine like terms: 1 + -8 = -7
4[-7 + 6x] = 3(2x + -7)
[-7 * 4 + 6x * 4] = 3(2x + -7)
[-28 + 24x] = 3(2x + -7)

Reorder the terms:
-28 + 24x = 3(-7 + 2x)
-28 + 24x = (-7 * 3 + 2x * 3)
-28 + 24x = (-21 + 6x)

Solving
-28 + 24x = -21 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
-28 + 24x + -6x = -21 + 6x + -6x

Combine like terms: 24x + -6x = 18x
-28 + 18x = -21 + 6x + -6x

Combine like terms: 6x + -6x = 0
-28 + 18x = -21 + 0
-28 + 18x = -21

Add '28' to each side of the equation.
-28 + 28 + 18x = -21 + 28

Combine like terms: -28 + 28 = 0
0 + 18x = -21 + 28
18x = -21 + 28

Combine like terms: -21 + 28 = 7
18x = 7

Divide each side by '18'.
x = 0.3888888889

Simplifying
x = 0.3888888889

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